From: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
---|---|
To: | Martin Mueller <martinmueller(at)northwestern(dot)edu> |
Cc: | "pgsql-general(at)lists(dot)postgresql(dot)org" <pgsql-general(at)lists(dot)postgresql(dot)org>, "pgsql-hackers(at)postgresql(dot)org" <pgsql-hackers(at)postgresql(dot)org> |
Subject: | Re: computing z-scores |
Date: | 2018-05-24 15:22:26 |
Message-ID: | CAKFQuwZP1JiUTL5DqzNMQMOw8cpgCjejo-AjXeLB3RQkb8wCWw@mail.gmail.com |
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Lists: | pgsql-general pgsql-hackers |
On Thu, May 24, 2018 at 8:15 AM, Martin Mueller <
martinmueller(at)northwestern(dot)edu> wrote:
> You construct a z-score for a set of values by subtracting the average
> from the value and dividing the result by the standard deviation. I know
> how to do this in a two-step procedure. First, I compute the average and
> standard deviation. In a second run I use the formula and apply it to each
> value.
>
> Is there a way of doing this in a single-step procedure or can you chain
> the two parts together in one query? This goes beyond my SQL competence.
>
Window functions provide the easiest means to apply aggregated values to
individual rows.
SELECT v, (v - (AVG(v) OVER ()) / (stddev(v) OVER ())) AS z_v
FROM (
VALUES (1),(2),(3)
) vals (v);
//-1, 0, 1
/docs/10/static/tutorial-window.html
David J.
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